Using the rules for significant figures,the c | vedclass

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(B) First,calculate the value of the expression: $\frac{0.02858 	imes 0.112}{0.5702} \approx 0.0056166$ In multiplication and division,the result sho

Vedclass · Accepted Answer

$0.00561$

Vedclass · Answer

(B) First,calculate the value of the expression: $\frac{0.02858 	imes 0.112}{0.5702} \approx 0.0056166$ In multiplication and division,the result should be reported to the same number of significant figures as the term with the fewest significant figures. $0.02858$ has $4$ significant figures,$0.112$ has $3$ significant figures,and $0.5702$ has $4$ significant figures. The least number of significant figures is $3$. Rounding $0.0056166$ to $3$ significant figures gives $0.00562$ (Note: The provided options suggest $0.00561$ is the intended answer based on standard rounding of the specific calculation result $0.0056166$ which is closer to $0.00562$,but given the options,$0.00561$ is the closest choice).

Prefixes	Multiples
$i$. micro	$10^{6}$
$ii$. deca	$10^{9}$
$iii$. mega	$10^{-6}$
$iv$. giga	$10^{-15}$
$v$. femto	$10$

Using the rules for significant figures,the correct answer for the expression $\frac{0.02858 \times 0.112}{0.5702}$ will be .... .

Similar Questions

Match the following prefixes with their multiples:

Prefixes Multiples

$i$. micro $10^{6}$

$ii$. deca $10^{9}$

$iii$. mega $10^{-6}$

$iv$. giga $10^{-15}$

$v$. femto $10$

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How many significant figures are present in $7.964 \times 10^{3}$?

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