Values of dissociation constant,K_a are given | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The strength of an acid is directly proportional to its dissociation constant $K_a$. Given $K_a$ values: $HCN$ $(6.2 	imes 10^{-10})$,$HNO_2$ $(4

Vedclass · Accepted Answer

$F^{-} < NO_2^- < CN^{-}$

Vedclass · Answer

(C) The strength of an acid is directly proportional to its dissociation constant $K_a$. Given $K_a$ values: $HCN$ $(6.2 	imes 10^{-10})$,$HNO_2$ $(4.0 	imes 10^{-4})$,$HF$ $(7.2 	imes 10^{-4})$. Thus,the order of acidic strength is $HCN Since the conjugate base of a stronger acid is a weaker base,the order of base strength is the inverse of the acidic strength. Therefore,the order of increasing base strength is $F^{-} < NO_2^- < CN^{-}$.

Values of dissociation constant,$K_a$ are given as follows:
Acid $K_a$
$HCN$ $6.2 \times 10^{-10}$
$HF$ $7.2 \times 10^{-4}$
$HNO_2$ $4.0 \times 10^{-4}$

Correct order of increasing base strength of the bases $CN^{-}$,$F^{-}$ and $NO_2^-$ will be:

Similar Questions

What is the conjugate acid of $HPO_4^{2-}$?

At $25^{\circ} C$,$K_{a}$ of formic acid is $1.8 \times 10^{-4}$. What is the $K_{b}$ of $HCOO^{-}$?

Water is a

Which of the following acts as an acid in an aqueous solution?

In which of the following neutralisation reactions will the heat of neutralisation be the highest?

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Acid	$K_a$
$HCN$	$6.2 \times 10^{-10}$
$HF$	$7.2 \times 10^{-4}$
$HNO_2$	$4.0 \times 10^{-4}$

Values of dissociation constant,$K_a$ are given as follows:Acid$K_a$$HCN$$6.2 \times 10^{-10}$$HF$$7.2 \times 10^{-4}$$HNO_2$$4.0 \times 10^{-4}$Correct order of increasing base strength of the bases $CN^{-}$,$F^{-}$ and $NO_2^-$ will be: