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(D) For a particle in simple harmonic motion, the acceleration $A$ is related to displacement $x$ by the equation $A = -\omega^2 x$, where $\omega$ is

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$\pi \; s$

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(D) For a particle in simple harmonic motion, the acceleration $A$ is related to displacement $x$ by the equation $A = -\omega^2 x$, where $\omega$ is the angular frequency.Taking the magnitude, we have $|A| = \omega^2 |x|$, which implies $\omega^2 = \frac{|A|}{|x|}$.Using the values from the table, for $x = 4 \; mm$, $A = -16 \; mm \; s^{-2}$.Thus, $\omega^2 = \frac{16}{4} = 4 \; s^{-2}$.Taking the square root, we get $\omega = 2 \; rad \; s^{-1}$.The time period $T$ is given by $T = \frac{2\pi}{\omega}$.Substituting the value of $\omega$, we get $T = \frac{2\pi}{2} = \pi \; s$.

$A \; (mm \; s^{-2})$	$16$	$8$	$0$	$-8$	$-16$
$x \; (mm)$	$-4$	$-2$	$0$	$2$	$4$

Values of the acceleration $A$ of a particle moving in simple harmonic motion as a function of its displacement $x$ are given in the table below. The period of the motion is
$A \; (mm \; s^{-2})$ $16$ $8$ $0$ $-8$ $-16$
$x \; (mm)$ $-4$ $-2$ $0$ $2$ $4$

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Values of the acceleration $A$ of a particle moving in simple harmonic motion as a function of its displacement $x$ are given in the table below. The period of the motion is$A \; (mm \; s^{-2})$$16$$8$$0$$-8$$-16$$x \; (mm)$$-4$$-2$$0$$2$$4$