Vapour density of a metal chloride is 83. If | vedclass

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(B) The molecular weight of the metal chloride is $2 	imes 	ext{vapour density} = 2 	imes 83 = 166$. Let the valency of the metal be $n$. The formu

Vedclass · Accepted Answer

$24$

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(B) The molecular weight of the metal chloride is $2 	imes 	ext{vapour density} = 2 	imes 83 = 166$. Let the valency of the metal be $n$. The formula of the metal chloride is $MCl_n$. Molecular weight $= 	ext{Atomic weight of metal} + n 	imes 35.5$. Since $	ext{Atomic weight} = n 	imes 	ext{Equivalent weight} = n 	imes 6$,we have: $166 = 6n + 35.5n$. $166 = 41.5n$. $n = \frac{166}{41.5} = 4$. Atomic weight of metal $= n 	imes 	ext{Equivalent weight} = 4 	imes 6 = 24$. Hence,the correct option is $B$.

Vapour density of a metal chloride is $83$. If equivalent weight of the metal is $6$,its atomic weight will be . . . . . . .

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