The variation of radiant energy emitted by th | vedclass

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Question

(C) According to Wien's displacement law, $\lambda_m T = 	ext{constant}$, which implies that the wavelength $\lambda_m$ corresponding to the maximum

Vedclass · Accepted Answer

Sun-$T_3$, tungsten filament-$T_1$, welding arc-$T_2$

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(C) According to Wien's displacement law, $\lambda_m T = 	ext{constant}$, which implies that the wavelength $\lambda_m$ corresponding to the maximum emission of energy is inversely proportional to the temperature $T$ of the source.As the temperature increases, the peak of the spectral emissive power curve shifts towards shorter wavelengths.Comparing the temperatures of the given sources: The temperature of the sun is approximately $6000 \, K$, the temperature of a welding arc is approximately $4000 \, K$ to $5000 \, K$, and the temperature of a tungsten filament is approximately $2000 \, K$ to $3000 \, K$.Therefore, $T_{	ext{sun}} > T_{	ext{welding arc}} > T_{	ext{tungsten filament}}$.Looking at the graph, the peak wavelength $\lambda_m$ is smallest for $T_3$ and largest for $T_1$.Thus, $T_3$ corresponds to the highest temperature (Sun), $T_2$ corresponds to the welding arc, and $T_1$ corresponds to the lowest temperature (tungsten filament).So, the correct match is: Sun-$T_3$, tungsten filament-$T_1$, welding arc-$T_2$.

The variation of radiant energy emitted by the sun, the filament of a tungsten lamp, and a welding arc as a function of its wavelength is shown in the figure. Which of the following options is the correct match?

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