(B) To verify if $x=3$ is a solution of the quadratic equation $6x^{2}-x-2=0$,we substitute $x=3$ into the expression $6x^{2}-x-2$.Substituting $x=3$:

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(B) To verify if $x=3$ is a solution of the quadratic equation $6x^{2}-x-2=0$,we substitute $x=3$ into the expression $6x^{2}-x-2$.Substituting $x=3$:$6(3)^{2} - (3) - 2$$= 6(9) - 3 - 2$$= 54 - 3 - 2$$= 49$Since the result $49 \neq 0$,the value $x=3$ does not satisfy the equation.Therefore,$x=3$ is not a solution of the quadratic equation $6x^{2}-x-2=0$.

Class 10 Mathematics Quadratic Equations Mix Examples - Quadratic Equations

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Verify whether the given value of $x$ is a solution of the quadratic equation or not: $6x^{2}-x-2=0, x=3$.

A
Yes,it is a solution.
B
No,it is not a solution.
C
It is a root of the equation.
D
Cannot be determined.

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Mix Examples - Quadratic Equations

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Solve the following equation using the method of factorization: $\frac{x+1}{x-1}-\frac{x-1}{x+1}=\frac{5}{6} \,(x \neq 1, -1)$

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Verify whether the given value of $x$ is a solution of the quadratic equation or not: $6x^{2}-x-2=0, x=3$.

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Find the roots of the following quadratic equations by the factorisation method:$\frac{2}{5} x^{2}-x-\frac{3}{5}=0$

Find the roots of the following quadratic equation by using the quadratic formula,if they exist: $2x^{2} - 2\sqrt{6}x + 3 = 0$

Find the discriminant of the following quadratic equation and hence determine the nature of the roots of the equation: $x^{2} + x + \frac{1}{4} = 0$.

The value of discriminant $D$ of the quadratic equation $25x^{2} - 10x + 1 = 0$ is ..... .

Solve the following equation using the method of factorization: $\frac{x+1}{x-1}-\frac{x-1}{x+1}=\frac{5}{6} \,(x \neq 1, -1)$

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Find the roots of the following quadratic equations by the factorisation method:
$\frac{2}{5} x^{2}-x-\frac{3}{5}=0$