Voltage and current in an ac circuit are give | vedclass

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(C) The given equations are $V = 5\sin(100\pi t - \frac{\pi}{6})$ and $I = 4\sin(100\pi t + \frac{\pi}{6})$.Comparing these with the standard forms $V

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Current leads the voltage by $60^o$

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(C) The given equations are $V = 5\sin(100\pi t - \frac{\pi}{6})$ and $I = 4\sin(100\pi t + \frac{\pi}{6})$.Comparing these with the standard forms $V = V_m\sin(\omega t + \phi_1)$ and $I = I_m\sin(\omega t + \phi_2)$,we get the phase angles as $\phi_1 = -\frac{\pi}{6}$ and $\phi_2 = \frac{\pi}{6}$.The phase difference is $\Delta \phi = \phi_2 - \phi_1 = \frac{\pi}{6} - (-\frac{\pi}{6}) = \frac{2\pi}{6} = \frac{\pi}{3}$.Since $\frac{\pi}{3}$ radians is equal to $60^o$ and $\phi_2 > \phi_1$,the current leads the voltage by $60^o$.

Voltage and current in an $ac$ circuit are given by $V = 5\sin(100\pi t - \frac{\pi}{6})$ and $I = 4\sin(100\pi t + \frac{\pi}{6})$. Which of the following statements is correct?

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