Volume of $0.5 \ mole$ of a gas at $1 \ atm$ pressure and $273 \ K$ is ............. $litres$.

Calculate the volume of $6.022 \times 10^{21}$ molecules of $CO_2$ at $300 \ K$ temperature and $2 \ bar$ pressure. $[R = 8.314 \times 10^{-2} \ bar \ L \ K^{-1} \ mol^{-1}]$ (in $mL$)

$0.5 \, mol$ of gas $A$ and $x \, mol$ of gas $B$ exert a pressure of $200 \, Pa$ in a container of volume $10 \, m^3$ at $1000 \, K$. Given $R$ is the gas constant in $J \, K^{-1} \, mol^{-1}$,$x$ is

$A$ container is filled with nitrogen gas at a certain temperature and pressure. The mass of the gas is $0.6 \ g$. Now,the container is filled with another gas at the same temperature and pressure. If the mass of the second gas under the given conditions is $0.73 \ g$,identify the gas.

At a temperature of $300 \ K$,if the pressure of $0.09 \ mol$ of a gas is halved,what will be its volume?

The volume-temperature graphs of a given mass of an ideal gas at different constant pressures are shown below. What is the correct order of pressures?