Volume of air needed for complete combustion | vedclass

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(D) The combustion reaction for ethene is:$C_2H_4 + 3O_2 \rightarrow 2CO_2 + 2H_2O$From the stoichiometry,$1 \ L$ of $C_2H_4$ requires $3 \ L$ of $O_2

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$150$

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(D) The combustion reaction for ethene is:$C_2H_4 + 3O_2 ightarrow 2CO_2 + 2H_2O$From the stoichiometry,$1 \ L$ of $C_2H_4$ requires $3 \ L$ of $O_2$ for complete combustion.Therefore,$10 \ L$ of $C_2H_4$ requires $10 	imes 3 = 30 \ L$ of $O_2$.Since air contains $20\%$ of $O_2$ by volume,the volume of air required is:$	ext{Volume of air} = \frac{	ext{Volume of } O_2}{0.20} = \frac{30 \ L}{0.20} = 150 \ L$.

Volume of air needed for complete combustion of $10 \ L$ of $C_2H_4$ is :
$($Assume air contains $20\%$ of $O_2$ by volume$)$ (in $L$)

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Volume of air needed for complete combustion of $10 \ L$ of $C_2H_4$ is :$($Assume air contains $20\%$ of $O_2$ by volume$)$ (in $L$)