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$(A)$ According to the equation of continuity, $A_1v_1 = A_2v_2$. When the cross-section $A$ of the duct decreases, the velocity $v$ of the water must

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$(A)$ According to the equation of continuity, $A_1v_1 = A_2v_2$. When the cross-section $A$ of the duct decreases, the velocity $v$ of the water must increase to maintain a constant flow rate.According to Bernoulli's theorem for horizontal flow, $P + \frac{1}{2}ho v^2 = 	ext{constant}$.As the velocity $v$ increases in the narrower section, the pressure $P$ must decrease to satisfy the equation.Therefore, the pressure remains constant in the wider section, drops as the duct narrows, and then remains constant at a lower value in the narrower section. This corresponds to the graph where pressure $p$ decreases as the cross-section decreases.

Water flows through a frictionless duct with a cross-section varying as shown in the figure. The pressure $p$ at points along the axis is represented by:

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