Water is flowing continuously from a tap havi | vedclass

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(C) Using the equation of motion $v_2^2 = v_1^2 + 2gh$,where $v_1 = 0.04\, ms^{-1}$,$g = 10\, ms^{-2}$,and $h = 8 	imes 10^{-1}\, m$:$v_2^2 = (0.04)^

Vedclass · Accepted Answer

$0.8 	imes 10^{-3}\, m$

Vedclass · Answer

(C) Using the equation of motion $v_2^2 = v_1^2 + 2gh$,where $v_1 = 0.04\, ms^{-1}$,$g = 10\, ms^{-2}$,and $h = 8 	imes 10^{-1}\, m$:$v_2^2 = (0.04)^2 + 2 	imes 10 	imes 0.8 = 0.0016 + 16 = 16.0016 \approx 16\, m^2s^{-2}$.Thus,$v_2 \approx 4\, ms^{-1}$.Using the equation of continuity $A_1v_1 = A_2v_2$,where $A = \pi (D/2)^2$:$D_1^2 v_1 = D_2^2 v_2$$(8 	imes 10^{-3})^2 	imes 0.04 = D_2^2 	imes 4$$64 	imes 10^{-6} 	imes 0.04 = D_2^2 	imes 4$$D_2^2 = 16 	imes 10^{-6} 	imes 0.04 = 0.64 	imes 10^{-6}$$D_2 = \sqrt{0.64 	imes 10^{-6}} = 0.8 	imes 10^{-3}\, m$.

Water is flowing continuously from a tap having an internal diameter $8 \times 10^{-3}\, m$. The water velocity as it leaves the tap is $0.04\, ms^{-1}$. The diameter of the water stream at a distance $8 \times 10^{-1}\, m$ below the tap is close to

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