Water rises up to a height $h$ in a capillary tube on the surface of the earth. The value of $h$ will increase if the experimental setup is kept in:

Two capillary tubes $P$ and $Q$ are dipped in water. The height of the water level in capillary $P$ is $2/3$ of the height in capillary $Q$. The ratio of their diameters is:

The sap in a tree rises in a system of capillaries of radius $2.5 \times 10^{-5} \, m$. The surface tension of the sap is $7.28 \times 10^{-2} \, N \, m^{-1}$ and the angle of contact is $0^{\circ}$. The maximum height to which the sap can rise in a tree through capillarity action is ...... $m$ (take $\rho_{sap} = 10^3 \, kg \, m^{-3}$ and $g = 9.8 \, m \, s^{-2}$).

Water rises to a height of $10 \, cm$ in a capillary tube and mercury falls to a depth of $3.1 \, cm$ in the same capillary tube. If the density of mercury is $13.6 \, g/cm^3$ and the angle of contact for mercury is $135^{\circ}$,the approximate ratio of surface tensions of water and mercury is

When one end of a capillary tube is dipped in water,the height of water column is $h$. The upward force of $105 \text{ dyne}$ due to surface tension is balanced by the force due to the weight of water column. The inner circumference of the capillary tube is (Surface tension of water $= 7 \times 10^{-2} \text{ N/m}$) (in $\text{ cm}$)

$A$ capillary tube of radius $0.1 \ mm$ is partly dipped in water (surface tension $70 \ dyn/cm$ and glass-water contact angle $\simeq 0^{\circ}$) inclined at $30^{\circ}$ with the vertical. The length of water risen in the capillary is . . . . . . $cm$. (Take $g = 980 \ cm/s^2$)