Wavelengths of light used in an optical instr | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The resolving power $(RP)$ of an optical instrument is given by the formula:$RP = \frac{2 \mu \sin 	heta}{1.22 \lambda}$From this expression, we

Vedclass · Accepted Answer

$5: 4$

Vedclass · Answer

(D) The resolving power $(RP)$ of an optical instrument is given by the formula:$RP = \frac{2 \mu \sin 	heta}{1.22 \lambda}$From this expression, we can see that the resolving power is inversely proportional to the wavelength of light used:$RP \propto \frac{1}{\lambda}$Therefore, the ratio of the resolving powers ($R_1$ and $R_2$) corresponding to wavelengths $\lambda_1$ and $\lambda_2$ is:$\frac{R_1}{R_2} = \frac{\lambda_2}{\lambda_1}$Given $\lambda_1 = 4000 \ Å$ and $\lambda_2 = 5000 \ Å$, we substitute these values:$\frac{R_1}{R_2} = \frac{5000}{4000} = \frac{5}{4}$Thus, the ratio is $5: 4$.

Wavelengths of light used in an optical instrument are $\lambda_1 = 4000 \ Å$ and $\lambda_2 = 5000 \ Å$. The ratio of their respective resolving powers (corresponding to $\lambda_1$ and $\lambda_2$) is:

Similar Questions

If $t_n$ denotes the number of triangles formed with $n$ points in a plane,no three of which are collinear,and if $t_{n+1}-t_n=36$,then $n$ is equal to

The limiting friction between two bodies in contact is independent of

Identify $acetaldoxime$.

$138 \ g$ of ethyl alcohol is mixed with $72 \ g$ of water. The ratio of mole fraction of alcohol to water is

In $YDSE$, the separation between the slits is halved and the distance between the slit and the screen is doubled. The fringe width is

Vedclass Test Series

Exam Paper Generator

Online Exam Module