Weight (g) of two moles of the organic compou | vedclass

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(C) The reaction of sodium ethanoate $(CH_3COONa)$ with soda lime $(NaOH + CaO)$ is known as decarboxylation.The chemical reaction is: $CH_3COONa + Na

Vedclass · Accepted Answer

$32$

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(C) The reaction of sodium ethanoate $(CH_3COONa)$ with soda lime $(NaOH + CaO)$ is known as decarboxylation.The chemical reaction is: $CH_3COONa + NaOH \xrightarrow{CaO} CH_4(g) + Na_2CO_3(s)$.The organic compound obtained is methane $(CH_4)$.The molar mass of $CH_4 = 12 + (4 	imes 1) = 16 \, g/mol$.The weight of $2$ moles of $CH_4 = 2 \, mol 	imes 16 \, g/mol = 32 \, g$.

Weight $(g)$ of two moles of the organic compound,which is obtained by heating sodium ethanoate with sodium hydroxide in the presence of calcium oxide is:

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