What amount of bromine will be required to co | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The reaction of phenol with bromine water is: $C_6H_5OH + 3Br_2 ightarrow C_6H_2Br_3OH + 3HBr$Molar mass of phenol $(C_6H_5OH) = (6 	imes 12) +

Vedclass · Accepted Answer

$10.22$

Vedclass · Answer

(A) The reaction of phenol with bromine water is: $C_6H_5OH + 3Br_2 ightarrow C_6H_2Br_3OH + 3HBr$Molar mass of phenol $(C_6H_5OH) = (6 	imes 12) + (6 	imes 1) + 16 = 72 + 6 + 16 = 94 \ g \ mol^{-1}$.Moles of phenol = $\frac{2 \ g}{94 \ g \ mol^{-1}} = 0.02128 \ mol$.According to the stoichiometry,$1 \ mol$ of phenol reacts with $3 \ mol$ of $Br_2$.Moles of $Br_2$ required = $3 	imes 0.02128 = 0.06384 \ mol$.Molar mass of $Br_2 = 2 	imes 80 = 160 \ g \ mol^{-1}$.Mass of $Br_2$ required = $0.06384 \ mol 	imes 160 \ g \ mol^{-1} = 10.2144 \ g \approx 10.22 \ g$.

What amount of bromine will be required to convert $2 \ g$ of phenol into $2, 4, 6-$tribromophenol (in $g$)? $($Given molar mass in $g \ mol^{-1}$ of $C, H, O, Br$ are $12, 1, 16, 80$ respectively$)$

Similar Questions

Explain why $p-$nitrophenol is more acidic than $o-$nitrophenol?

What is the product formed when sodium phenoxide reacts with $CO_2$ at $400 \ K$ temperature and $4.7 \ atm$ pressure?

The reaction is given as: $X \xrightarrow{Y} \text{Benzoquinone}$. Identify $X$ and $Y$ in the above reaction.

The reaction shown in the figure is known as:

Hybridisation shown by Carbon and Oxygen of $-OH$ group in phenol are respectively . . . . . . .

Vedclass Test Series

Exam Paper Generator

Online Exam Module