What are X and Y respectively in the followin | vedclass

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(B) The given reaction involves two different chemical transformations of benzamide $(C_6H_5CONH_2)$: $1$. Reaction with $LiAlH_4$ followed by $H_2O$:

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$C_6H_5NH_2$ and $C_6H_5CH_2NH_2$

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(B) The given reaction involves two different chemical transformations of benzamide $(C_6H_5CONH_2)$: $1$. Reaction with $LiAlH_4$ followed by $H_2O$: This is a reduction reaction. $LiAlH_4$ reduces the amide group $(-CONH_2)$ to an amine group $(-CH_2NH_2)$. Thus,$Y$ is benzylamine $(C_6H_5CH_2NH_2)$. $2$. Reaction with $Br_2$ and $NaOH$: This is the Hoffmann bromamide degradation reaction. It converts an amide $(-CONH_2)$ into a primary amine with one carbon atom less $(-NH_2)$. Thus,$X$ is aniline $(C_6H_5NH_2)$. Therefore,$X$ is $C_6H_5NH_2$ and $Y$ is $C_6H_5CH_2NH_2$.

What are $X$ and $Y$ respectively in the following reactions?

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