What are A and B in the following reaction se | vedclass

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(C) The reaction of a nitrile with a Grignard reagent $(RMgX)$ followed by acid hydrolysis yields a ketone.For the formation of propiophenone $(CH_3CH

Vedclass · Accepted Answer

$A = C_6H_5MgBr, B = CH_3CH_2C(NMgBr)C_6H_5$

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(C) The reaction of a nitrile with a Grignard reagent $(RMgX)$ followed by acid hydrolysis yields a ketone.For the formation of propiophenone $(CH_3CH_2-CO-C_6H_5)$,the starting material is propionitrile $(CH_3CH_2-CN)$.The Grignard reagent $(A)$ must be phenylmagnesium bromide $(C_6H_5MgBr)$.The reaction proceeds as follows:$CH_3CH_2-C \equiv N + C_6H_5MgBr \longrightarrow CH_3CH_2-C(C_6H_5)=NMgBr$ $(B)$$CH_3CH_2-C(C_6H_5)=NMgBr + 2H_2O \xrightarrow{H_3O^{+}} CH_3CH_2-CO-C_6H_5 + NH_3 + Mg(OH)Br$Thus,$A$ is $C_6H_5MgBr$ and $B$ is $CH_3CH_2C(NMgBr)C_6H_5$.

What are $A$ and $B$ in the following reaction sequence?
$\text{Propionitrile} + A$ $\longrightarrow B$ $\xrightarrow{H_3O^{+}} \text{propiophenone}$

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What are $A$ and $B$ in the following reaction sequence?$\text{Propionitrile} + A$ $\longrightarrow B$ $\xrightarrow{H_3O^{+}} \text{propiophenone}$