What are X and Y in the following reaction se | vedclass

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(C) The given reaction proceeds as follows:$1$. The starting material is a chiral $2^{\circ}$ haloalkane,specifically $(S)-2-$bromobutane.$2$. The rea

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(C) The given reaction proceeds as follows:$1$. The starting material is a chiral $2^{\circ}$ haloalkane,specifically $(S)-2-$bromobutane.$2$. The reaction with $KCN$ proceeds via an $S_{N}2$ mechanism. The nucleophile $CN^-$ attacks from the side opposite to the leaving group $(Br^-)$,resulting in a Walden inversion of the configuration at the chiral center.$3$. This produces $(R)-2-$methylbutanenitrile as product $X$.$4$. Subsequent acid-catalyzed hydrolysis of the nitrile group $(-CN)$ converts it into a carboxylic acid group $(-COOH)$ without affecting the chiral center. Thus,the configuration remains inverted relative to the starting material,yielding $(R)-2-$methylbutanoic acid as product $Y$.$5$. Comparing this with the given options,option $C$ correctly represents the structures of $X$ and $Y$.

What are $X$ and $Y$ in the following reaction sequence?

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