What are Y and Z respectively in the followin | vedclass

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(B) $1$. The nitration of chlorobenzene with $conc. HNO_3$ and $conc. H_2SO_4$ yields $1$-chloro-$4$-nitrobenzene as the major product $(X)$ because t

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$(i)$ $NaOH, 443 \ K, (ii) H^+$; $4-$nitrophenol

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(B) $1$. The nitration of chlorobenzene with $conc. HNO_3$ and $conc. H_2SO_4$ yields $1$-chloro-$4$-nitrobenzene as the major product $(X)$ because the $-Cl$ group is ortho/para directing and the para-isomer is sterically favored.$2$. The conversion of $1$-chloro-$4$-nitrobenzene to $4$-nitrophenol involves nucleophilic aromatic substitution.$3$. The reaction requires strong nucleophilic conditions,which are provided by $(i) NaOH$ at $443 \ K$ followed by $(ii) H^+$ (acidification) to convert the phenoxide ion to the phenol.$4$. Thus,$Y$ is $(i) NaOH, 443 \ K, (ii) H^+$ and $Z$ is $4$-nitrophenol.

What are $Y$ and $Z$ respectively in the following reaction sequence?
Chlorobenzene $\xrightarrow[Conc. H_2SO_4]{HNO_3}$ $X$ (major product) $\xrightarrow{Y}$ $Z$

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What are $Y$ and $Z$ respectively in the following reaction sequence?Chlorobenzene $\xrightarrow[Conc. H_2SO_4]{HNO_3}$ $X$ (major product) $\xrightarrow{Y}$ $Z$