What are X and Y in the following reaction se | vedclass

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(B) $1$. The reaction of $n$-heptane $(CH_3(CH_2)_5CH_3)$ with $V_2O_5$ or $Cr_2O_3$ or $Mo_2O_3$ at $773 \ K$ and $10-20 \ atm$ pressure leads to aro

Vedclass · Accepted Answer

$X = V_2O_5, 773 \ K, 10-20 \ atm$,$Y = 	ext{benzyl bromide}$

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(B) $1$. The reaction of $n$-heptane $(CH_3(CH_2)_5CH_3)$ with $V_2O_5$ or $Cr_2O_3$ or $Mo_2O_3$ at $773 \ K$ and $10-20 \ atm$ pressure leads to aromatization,producing toluene $(C_7H_8)$.$2$. The subsequent reaction of toluene with $Br_2$ in the presence of heat $(\Delta)$ or light undergoes free radical substitution at the benzylic position to form benzyl bromide $(C_6H_5CH_2Br)$.

What are $X$ and $Y$ in the following reaction sequence?
$CH_3(CH_2)_5CH_3 \stackrel{X}{\longrightarrow} C_7H_8 \stackrel{Br_2}{\Delta} Y$

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What are $X$ and $Y$ in the following reaction sequence?$CH_3(CH_2)_5CH_3 \stackrel{X}{\longrightarrow} C_7H_8 \stackrel{Br_2}{\Delta} Y$