What are X and Y in the following reaction? H | vedclass

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(C) Reductive ozonolysis of $Hex-2-ene$ $(CH_3-CH_2-CH_2-CH=CH-CH_3)$ involves the addition of ozone across the double bond followed by cleavage with

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$X = CH_3-CH_2-CH_2-CHO, Y = CH_3-CHO$

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(C) Reductive ozonolysis of $Hex-2-ene$ $(CH_3-CH_2-CH_2-CH=CH-CH_3)$ involves the addition of ozone across the double bond followed by cleavage with $Zn/H_2O$ to produce two carbonyl compounds.Cleavage of the $C=C$ bond in $Hex-2-ene$ occurs at the $2^{nd}$ position.The reaction is: $CH_3-CH_2-CH_2-CH=CH-CH_3 \xrightarrow{O_3, Zn/H_2O} CH_3-CH_2-CH_2-CHO + CH_3-CHO$.Thus,$X = CH_3-CH_2-CH_2-CHO$ $(Butanal)$ and $Y = CH_3-CHO$ $(Ethanal)$.

What are $X$ and $Y$ in the following reaction? $Hex-2-ene$ $\xrightarrow{O_3} \text{Ozonide}$ $\xrightarrow{Zn + H_2O} X + Y$

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