What are X and Y in the following reaction se | vedclass

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(C) $1$. $Propene$ $(CH_3-CH=CH_2)$ reacts with $HBr$ to form $2-bromopropane$ $(A)$ $(CH_3-CH(Br)-CH_3)$.$2$. $2-bromopropane$ reacts with $Mg$ in $D

Vedclass · Accepted Answer

$X$ = Pentan$-3-$one,$Y$ = $3-$ethyl$-2-$methylpentan$-3-$ol

Vedclass · Answer

(C) $1$. $Propene$ $(CH_3-CH=CH_2)$ reacts with $HBr$ to form $2-bromopropane$ $(A)$ $(CH_3-CH(Br)-CH_3)$.$2$. $2-bromopropane$ reacts with $Mg$ in $Dry \ ether$ to form $isopropylmagnesium \ bromide$ $(B)$ $(CH_3-CH(MgBr)-CH_3)$.$3$. $Isopropylmagnesium \ bromide$ $(B)$ reacts with $Pentan-3-one$ $(X)$ $(CH_3CH_2-CO-CH_2CH_3)$ followed by acid hydrolysis $(H_3O^+)$ to form $3-ethyl-2-methylpentan-3-ol$ $(Y)$.

What are $X$ and $Y$ in the following reaction sequence?
$Propene$ $\xrightarrow{HBr} A$ $\xrightarrow[Dry \ ether]{Mg} B$ $\xrightarrow[2. H_3O^{+}]{1. X} Y$

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What are $X$ and $Y$ in the following reaction sequence?$Propene$ $\xrightarrow{HBr} A$ $\xrightarrow[Dry \ ether]{Mg} B$ $\xrightarrow[2. H_3O^{+}]{1. X} Y$