What are X and Y in the following reactions?( | vedclass

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(B) The reactions of permanganate ion $(MnO_4^{-})$ with iodide ion $(I^{-})$ depend on the medium.$(i)$ In acidic medium $(H^{+})$:$2 MnO_4^{-} + 10

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$I_2, IO_3^{-}$

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(B) The reactions of permanganate ion $(MnO_4^{-})$ with iodide ion $(I^{-})$ depend on the medium.$(i)$ In acidic medium $(H^{+})$:$2 MnO_4^{-} + 10 I^{-} + 16 H^{+} \longrightarrow 2 Mn^{2+} + 5 I_2 + 8 H_2O$Here,$X = I_2$.$(ii)$ In neutral or weakly alkaline medium $(H_2O)$:$2 MnO_4^{-} + I^{-} + H_2O \longrightarrow 2 MnO_2 + IO_3^{-} + 2 OH^{-}$Here,$Y = IO_3^{-}$.Therefore,$X$ and $Y$ are $I_2$ and $IO_3^{-}$ respectively.

What are $X$ and $Y$ in the following reactions?
$(i) \ MnO_4^{-} + I^{-} \xrightarrow{H^{+}} X$
$(ii) \ MnO_4^{-} + I^{-} \xrightarrow{H_2O} Y$

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What are $X$ and $Y$ in the following reactions?$(i) \ MnO_4^{-} + I^{-} \xrightarrow{H^{+}} X$$(ii) \ MnO_4^{-} + I^{-} \xrightarrow{H_2O} Y$