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(B) The reaction of iso-pentane ($2$-methylbutane) with $KMnO_4$ is an oxidation reaction that occurs at the tertiary carbon atom,which is the most re

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$2-$methylbutan$-2-$ol,$2$-methylbut$-2-$ene

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(B) The reaction of iso-pentane ($2$-methylbutane) with $KMnO_4$ is an oxidation reaction that occurs at the tertiary carbon atom,which is the most reactive site for oxidation in alkanes. This leads to the formation of $2$-methylbutan-$2$-ol as the major product $X$.$CH_3-CH(CH_3)-CH_2-CH_3 \xrightarrow{KMnO_4} CH_3-C(OH)(CH_3)-CH_2-CH_3$ $(X)$Next,the dehydration of $2$-methylbutan-$2$-ol $(X)$ in the presence of $20 \% H_3PO_4$ at $358 \ K$ follows Saytzeff's rule,which states that the more substituted alkene is the major product.$CH_3-C(OH)(CH_3)-CH_2-CH_3 \xrightarrow[358 \ K]{20 \% H_3PO_4} CH_3-C(CH_3)=CH-CH_3$ $(Y)$ + $H_2O$Thus,$X$ is $2$-methylbutan-$2$-ol and $Y$ is $2$-methylbut-$2$-ene.

What are $X$ and $Y$ in the following reaction sequence?
Iso-pentane $\xrightarrow{KMnO_4} X$ $\xrightarrow[358 \ K]{20 \% H_3PO_4} Y$

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What are $X$ and $Y$ in the following reaction sequence?Iso-pentane $\xrightarrow{KMnO_4} X$ $\xrightarrow[358 \ K]{20 \% H_3PO_4} Y$