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(D) In the first reaction,$(CH_3)_3CONa$ is a strong nucleophile and $CH_3CH_2Br$ is a primary alkyl halide. This undergoes an $S_N2$ reaction to form

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$(CH_3)_3COCH_2CH_3, (CH_3)_2C=CH_2$

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(D) In the first reaction,$(CH_3)_3CONa$ is a strong nucleophile and $CH_3CH_2Br$ is a primary alkyl halide. This undergoes an $S_N2$ reaction to form the ether $(CH_3)_3COCH_2CH_3$ $(X)$.In the second reaction,$(CH_3)_3CBr$ is a tertiary alkyl halide and $CH_3CH_2ONa$ is a strong base. Tertiary alkyl halides with strong bases undergo an $E2$ elimination reaction to form an alkene,which is $(CH_3)_2C=CH_2$ $(Y)$.

What are the major products $X$ and $Y$ respectively in the following reactions?
$(CH_3)_3CONa + CH_3CH_2Br \rightarrow X$
$(CH_3)_3CBr + CH_3CH_2ONa \rightarrow Y$

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What are the major products $X$ and $Y$ respectively in the following reactions?$(CH_3)_3CONa + CH_3CH_2Br \rightarrow X$$(CH_3)_3CBr + CH_3CH_2ONa \rightarrow Y$