What determines the direction of motion of an object: velocity or acceleration?
(A) The direction of motion of an object is determined by its velocity. Velocity is a vector quantity that includes both the magnitude (speed) and the direction of motion. Acceleration,on the other hand,represents the rate of change of velocity. While acceleration can change the magnitude or the direction of the velocity,it does not define the current direction of motion itself.
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$A$ circular cycle track has a circumference of $314 \ m$ with $AB$ as one of its diameters. $A$ cyclist travels from $A$ to $B$ along the circular path with a velocity of constant magnitude $15.7 \ m s^{-1}$. Find the:
$(a)$ distance moved by the cyclist.
$(b)$ displacement of the cyclist,if $AB$ represents the north-south direction.
$(c)$ the average velocity of the cyclist.
$(a)$ distance moved by the cyclist.
$(b)$ displacement of the cyclist,if $AB$ represents the north-south direction.
$(c)$ the average velocity of the cyclist.
Medium
View SolutionCan the displacement of a particle be zero when the distance travelled is not zero?
Easy
View Solution$(a)$ Derive the second equation of motion $S = ut + \frac{1}{2}at^2$ graphically,where the symbols have their usual meanings.
$(b)$ $A$ car accelerates uniformly from $18 \text{ km h}^{-1}$ to $36 \text{ km h}^{-1}$ in $5 \text{ s}$. Calculate the acceleration and the distance covered by the car in that time.
$(b)$ $A$ car accelerates uniformly from $18 \text{ km h}^{-1}$ to $36 \text{ km h}^{-1}$ in $5 \text{ s}$. Calculate the acceleration and the distance covered by the car in that time.
Difficult
View Solution$A$ particle is moving in a circular path of radius $r$. The displacement after half a circle would be:
Easy
View SolutionState whether the following statement is true or false:
$A$ motion is said to be uniform if $x \propto t^{2}$.
$A$ motion is said to be uniform if $x \propto t^{2}$.
Easy
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