What happens to the force between two magnetic poles when their pole strength and the distance between them are both doubled?

$A$ magnet,when placed perpendicular to a uniform magnetic field of strength $10^{-4} \ Wb/m^2$,experiences a maximum torque of $4 \times 10^{-5} \ N \cdot m$. What is its magnetic moment in $A \cdot m^2$?

Magnetic field intensity is defined as

The magnetic moment of the arrangement shown in the figure is ............. $M$.

Each atom of an iron bar $(5 \, cm \times 1 \, cm \times 1 \, cm)$ has a magnetic moment of $1.8 \times 10^{-23} \, A \cdot m^2$. Given that the density of iron is $7.78 \times 10^3 \, kg/m^3$,the atomic weight is $56 \, g/mol$,and Avogadro's number is $6.02 \times 10^{23} \, mol^{-1}$,calculate the magnetic moment of the bar in the state of magnetic saturation in $A \cdot m^2$.

$A$ magnetised wire of magnetic moment $3.14 \, A-m^2$ is bent in the form of a semi-circle. The new magnetic moment will be.....$A-m^2$