What is A in the following reaction?3text{-io | vedclass

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(D) The reaction involves the nucleophilic substitution of the chlorine atom in $3	ext{-iodobenzyl chloride}$ with a cyanide ion $(CN^-)$.The reagent

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$3-$iodobenzyl cyanide

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(D) The reaction involves the nucleophilic substitution of the chlorine atom in $3	ext{-iodobenzyl chloride}$ with a cyanide ion $(CN^-)$.The reagent $NaCN$ in $DMF$ (a polar aprotic solvent) promotes the $S_N2$ reaction.The benzylic carbon is highly reactive towards $S_N2$ substitution due to the stability of the transition state.The iodine atom attached to the benzene ring is much less reactive towards nucleophilic substitution compared to the benzylic chloride.Therefore,the $CN^-$ ion selectively replaces the $Cl$ atom at the benzylic position,resulting in $3	ext{-iodobenzyl cyanide}$ (also known as $2	ext{-(3-iodophenyl)acetonitrile}$).The correct option is $D$.

What is $A$ in the following reaction?
$3\text{-iodobenzyl chloride} \xrightarrow{NaCN, DMF} A$

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What is $A$ in the following reaction?$3\text{-iodobenzyl chloride} \xrightarrow{NaCN, DMF} A$