What is X in the given reaction?HOCH_2-CH_2OH | vedclass

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(A) The reaction of ethylene glycol $(HOCH_2-CH_2OH)$ with oxalic acid $((COOH)_2)$ at $110^{\circ}C$ forms a cyclic ester (ethylene oxalate).Upon fur

Vedclass · Accepted Answer

$CH_2=CH_2$

Vedclass · Answer

(A) The reaction of ethylene glycol $(HOCH_2-CH_2OH)$ with oxalic acid $((COOH)_2)$ at $110^{\circ}C$ forms a cyclic ester (ethylene oxalate).Upon further heating to $210^{\circ}C$,this cyclic ester undergoes decarboxylation to produce ethene $(CH_2=CH_2)$ and carbon dioxide $(CO_2)$.Therefore,the major product $X$ formed at $210^{\circ}C$ is ethene $(CH_2=CH_2)$.

What is $X$ in the given reaction?
$HOCH_2-CH_2OH + (COOH)_2 \xrightarrow{210^{\circ}C} X$
(major product)

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What is $X$ in the given reaction?$HOCH_2-CH_2OH + (COOH)_2 \xrightarrow{210^{\circ}C} X$(major product)