What is X in the following reaction? | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The given reaction shows that $C_6H_{10}$ (cyclohexene) reacts with $KMnO_4-H_2SO_4$ to form adipic acid (hexanedioic acid),which is a standard ox

Vedclass · Accepted Answer

$3-$bromocyclohex$-1-$ene

Vedclass · Answer

(A) The given reaction shows that $C_6H_{10}$ (cyclohexene) reacts with $KMnO_4-H_2SO_4$ to form adipic acid (hexanedioic acid),which is a standard oxidative cleavage reaction of cyclohexene. When cyclohexene $(C_6H_{10})$ reacts with $Br_2$ in the presence of $UV$ light,it undergoes allylic bromination. The allylic position in cyclohexene is the carbon adjacent to the double bond. Therefore,the product $X$ is $3$-bromocyclohex-$1$-ene.

What is $X$ in the following reaction?

Similar Questions

The reaction of propene with $HOCl$ proceeds via the addition of which of the following in the first step?

The number of alkenyl groups possible from $C_{4}H_{7}$ are

An optically active compound $A$ with molecular formula $C_8H_{14}$ undergoes catalytic hydrogenation to give a meso compound. The structure of $(A)$ is:

The reaction of $CH_3-CH=C(CH_3)-CH=CH_2$ with $(1) \ O_3$ followed by $(2) \ H_2O, Zn$ gives which products?

The major product of the following reaction is $F_3C-CH=CH_2 + HBr \rightarrow$

Vedclass Test Series

Exam Paper Generator

Online Exam Module