What is $B$ in the given reaction?
$C_2H_5Br \xrightarrow{\text{excess } NH_3} A \xleftarrow{Br_2/KOH} B$

  • A
    Propanamide $(CH_3CH_2CONH_2)$
  • B
    Acetamide $(CH_3CONH_2)$
  • C
    $N$-methylpropanamide $(CH_3CH_2CONHCH_3)$
  • D
    Propan$-2-$amine $(CH_3CH(NH_2)CH_3)$

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