What is the final product of this reaction?

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(C) The given reaction is a cross-Cannizzaro reaction between $p$-nitrobenzaldehyde and $p$-methylbenzaldehyde in the presence of a base $(OH^-)$.In a

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$A$ mixture of $p$-nitrobenzoate ion and $p$-methylbenzyl alcohol.

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(C) The given reaction is a cross-Cannizzaro reaction between $p$-nitrobenzaldehyde and $p$-methylbenzaldehyde in the presence of a base $(OH^-)$.In a cross-Cannizzaro reaction,the more electrophilic aldehyde is reduced to the corresponding alcohol,while the less electrophilic aldehyde is oxidized to the corresponding carboxylate ion.$p$-Nitrobenzaldehyde has an electron-withdrawing $-NO_2$ group,making its carbonyl carbon more electrophilic.$p$-Methylbenzaldehyde has an electron-donating $-CH_3$ group,making its carbonyl carbon less electrophilic.Therefore,$p$-nitrobenzaldehyde is reduced to $p$-nitrobenzyl alcohol,and $p$-methylbenzaldehyde is oxidized to the $p$-methylbenzoate ion.The correct products are $p$-nitrobenzyl alcohol and $p$-methylbenzoate ion.

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