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(A) The reaction of $p$-hydroxybenzoic acid with excess $Br_2$ in $H_2O$ leads to electrophilic aromatic substitution. The $-OH$ group is a strongly a

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$2,4,6-$Tribromophenol

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(A) The reaction of $p$-hydroxybenzoic acid with excess $Br_2$ in $H_2O$ leads to electrophilic aromatic substitution. The $-OH$ group is a strongly activating and $o/p$-directing group,while the $-COOH$ group is a deactivating and $m$-directing group. Due to the strong activating effect of the $-OH$ group,bromination occurs at the positions ortho to the $-OH$ group. Since the para position is already occupied by the $-COOH$ group,the bromine atoms substitute the hydrogen atoms at the two ortho positions relative to the $-OH$ group. However,in the presence of excess $Br_2$ and $H_2O$,the $-COOH$ group can also be displaced by bromine (decarboxylation-bromination),leading to the formation of $2,4,6$-tribromophenol.

What is the product of the following reaction?

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