What is the stereochemistry of the product formed in the following reaction?

The product of the reaction shown is:

Action of hydrogen chloride on $CH_3-C(CH_3)=CH_2$ and on $CH \equiv CH$ will predominantly give the compounds,respectively:

Match the following reactions in List-$I$ with their products in List-$II$:
| List-$I$ | List-$II$ |
| :--- | :--- |
| $A. HC \equiv CH \xrightarrow{Hg^{2+}, H^{+}/H_{2}O}$ | $I. H_{3}C-COOH$ |
| $B. CH_{4} \xrightarrow{O_{2}, Mo_{2}O_{3}, \Delta}$ | $II. CH_{3}-CO-CH_{3}$ |
| $C. (CH_{3})_{2}C=C(CH_{3})_{2} \xrightarrow{O_{3}, Zn, H_{2}O}$ | $III. H_{3}C-CHO$ |
| $D. CH_{3}-CH=CH-CH_{3} \xrightarrow{KMnO_{4}, H^{+}}$ | $IV. HCHO$ |

Propane can be separated from propene by using......

$A \xrightarrow{\Delta, 800^\circ C} CH_2=C=O$. Reactant '$A$' in the reaction is: