What is surface energy?
(N/A) Surface energy is defined as the amount of work done in increasing the surface area of a liquid by a unit amount at a constant temperature.
It is numerically equal to the surface tension of the liquid.
Mathematically,if $W$ is the work done to increase the surface area by $\Delta A$,then the surface energy $S$ is given by $S = \frac{W}{\Delta A}$.
The $SI$ unit of surface energy is $J/m^2$ or $N/m$.
It is numerically equal to the surface tension of the liquid.
Mathematically,if $W$ is the work done to increase the surface area by $\Delta A$,then the surface energy $S$ is given by $S = \frac{W}{\Delta A}$.
The $SI$ unit of surface energy is $J/m^2$ or $N/m$.
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Similar Questions
$A$ water drop of radius $1\,cm$ is broken into $729$ equal droplets. If the surface tension of water is $75\,dyne/cm$,then the gain in surface energy up to the first decimal place will be $...\times 10^{-4}\,J$.
$A$ soap bubble of surface tension $0.04 \ N/m$ is blown to a diameter of $7 \ cm$. If $(15000 - x) \ \mu J$ of work is done in blowing it further to make its diameter $14 \ cm$, then the value of $x$ is . . . . . . . (Take $\pi = 22/7$)
The amount of work done in blowing a soap bubble such that its diameter increases from $d$ to $D$ is ($T=$ surface tension of solution).
The area of a liquid film is $60\, cm^2$ and its surface tension is $T = 20\, dyne/cm$. What is the work done to increase its area to $120\, cm^2$ (in $, erg$)?
Medium
View SolutionThe surface tension of a liquid is $0.5 \, N/m$. If a film is held on a ring of area $0.02 \, m^2$,its surface energy is:
Easy
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