What is the pH of 1 times 10^{-4} M H_2SO_4 | vedclass

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(A) $H_2SO_4$ is a strong diprotic acid that dissociates completely in water as follows: $H_2SO_4 \rightarrow 2H^+ + SO_4^{2-}$ Since the concentratio

Vedclass · Accepted Answer

$3.70$

Vedclass · Answer

(A) $H_2SO_4$ is a strong diprotic acid that dissociates completely in water as follows: $H_2SO_4 ightarrow 2H^+ + SO_4^{2-}$ Since the concentration of $H_2SO_4$ is $1 	imes 10^{-4} \ M$,the concentration of $H^+$ ions is: $[H^+] = 2 	imes [H_2SO_4] = 2 	imes 1 	imes 10^{-4} \ M = 2 	imes 10^{-4} \ M$ The $pH$ is calculated as: $pH = -\log[H^+] = -\log(2 	imes 10^{-4})$ $pH = -(\log 2 + \log 10^{-4}) = -(0.301 - 4) = 3.699 \approx 3.70$

What is the $pH$ of $1 \times 10^{-4} \ M \ H_2SO_4$ solution?

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