What is the pOH value of a 10^{-4} ; M aqueou | vedclass

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(D) $HCl$ is a strong acid that dissociates completely in water as: $HCl \rightarrow H^+ + Cl^-$.Given the concentration of $HCl$ is $10^{-4} \; M$,th

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$10$

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(D) $HCl$ is a strong acid that dissociates completely in water as: $HCl \rightarrow H^+ + Cl^-$.Given the concentration of $HCl$ is $10^{-4} \; M$,the concentration of $H^+$ ions is $[H^+] = 10^{-4} \; M$.The $pH$ of the solution is calculated as: $pH = -\log[H^+] = -\log(10^{-4}) = 4$.Using the relationship $pH + pOH = 14$ at $25^{\circ}C$,we find $pOH = 14 - pH$.Therefore,$pOH = 14 - 4 = 10$.

What is the $pOH$ value of a $10^{-4} \; M$ aqueous solution of $HCl$?

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