What is the IUPAC name of the following compo | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) $1$. Identify the principal functional group: The $-OH$ group is the principal functional group,so the parent chain is a cyclopentanol.$2$. Number

Vedclass · Accepted Answer

$2-$Ethyl$-5-$methylcyclopentanol

Vedclass · Answer

(D) $1$. Identify the principal functional group: The $-OH$ group is the principal functional group,so the parent chain is a cyclopentanol.$2$. Numbering the ring: The carbon atom attached to the $-OH$ group is assigned position $1$. The ring is then numbered to give the lowest possible locants to the substituents.$3$. If we number clockwise,the substituents are at positions $2$ (ethyl) and $5$ (methyl). If we number counter-clockwise,the substituents are at positions $2$ (methyl) and $5$ (ethyl).$4$. Applying the lowest locant rule: Comparing the sets $(2, 5)$ and $(2, 5)$,we look at alphabetical order. Ethyl comes before methyl.$5$. Therefore,we assign the lower number to the substituent that comes first alphabetically. Thus,the ethyl group is at position $2$ and the methyl group is at position $5$.$6$. The $IUPAC$ name is $2-$Ethyl$-5-$methylcyclopentanol.

$X$	$1$	$2$	$3$	$4$	$5$
$P(X)$	$k^2$	$2k$	$k$	$2k$	$5k^2$

What is the $IUPAC$ name of the following compound?

Similar Questions

The products formed when heavy water is reacted with magnesium nitride are:

$A$ random variable $X$ has the following probability distribution:
$X$ $1$ $2$ $3$ $4$ $5$
$P(X)$ $k^2$ $2k$ $k$ $2k$ $5k^2$

Then $P(X > 2)$ is equal to:

In a first order reaction,the concentration of the reactant decreases from $0.6 \ M$ to $0.3 \ M$ in $15 \ min$. The time taken for the concentration to change from $0.1 \ M$ to $0.025 \ M$ in minutes is

Assuming complete ionisation,the $pH$ of $0.1 \ M \ HCl$ is $1$. The molarity of $H_2SO_4$ with the same $pH$ is (in $M$)

In the figure shown,the power generated in $y$ is maximum when $y = 5\,\Omega$. Then $R$ is .............. $\Omega$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module