(B) The $pH$ is calculated using the formula: $pH = -\log_{10}[H^{+}]$. Given $[H^{+}] = 2.2 \times 10^{-6} \ M$. $pH = -\log_{10}(2.2 \times 10^{-6})

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(B) The $pH$ is calculated using the formula: $pH = -\log_{10}[H^{+}]$. Given $[H^{+}] = 2.2 \times 10^{-6} \ M$. $pH = -\log_{10}(2.2 \times 10^{-6}) = -(\log_{10}(2.2) + \log_{10}(10^{-6}))$. $pH = -(\log_{10}(2.2) - 6) = 6 - \log_{10}(2.2)$. Since $\log_{10}(2.2) \approx 0.34$,$pH = 6 - 0.34 = 5.66$.

Class 11 Chemistry 6-2.Equilibrium-II (Ionic Equilibrium)Water hydrolysis and pH scale

Medium

What is the $pH$ of a solution containing $2.2 \times 10^{-6} \ M$ hydrogen ions?

MHT CET 2023 All MHT CET

A
$6.34$
B
$5.66$
C
$4.34$
D
$3.8$

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6-2.Equilibrium-II (Ionic Equilibrium)

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Water hydrolysis and pH scale

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What is the $pH$ of a solution containing $2.2 \times 10^{-6} \ M$ hydrogen ions?

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