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(C) The electronic configuration of the $M^{2+}$ ion is $[Ar] 3d^8$.This means the neutral atom $M$ has lost $2$ electrons to form the $M^{2+}$ ion.To

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$28$

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(C) The electronic configuration of the $M^{2+}$ ion is $[Ar] 3d^8$.This means the neutral atom $M$ has lost $2$ electrons to form the $M^{2+}$ ion.To find the configuration of the neutral atom $M$,we add the $2$ electrons back to the $3d^8$ configuration.The configuration of the neutral atom $M$ is $[Ar] 3d^8 4s^2$.The total number of electrons in the neutral atom is $18$ (from $[Ar]$) $+ 8 + 2 = 28$.Therefore,the atomic number of the element is $28$.

What is the atomic number of the element with $M^{2+}$ ion having electronic configuration $[Ar] 3d^8$?

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