What is the boiling point of a solution of $0.1 \ m$ $KCl$ (in $K$)? $K_{b}$ of water is $0.52 \ K \ kg \ mol^{-1}$ and $\alpha = 100 \ \%$ (boiling point of pure water is $373 \ K$).

The boiling point of benzene is $353.23 \, K$. When $1.80 \, g$ of a non-volatile solute was dissolved in $90 \, g$ of benzene,the boiling point is raised to $354.11 \, K$. Calculate the molar mass of the solute. $K_{b}$ for benzene is $2.53 \, K \, kg \, mol^{-1}$.

If the solution boils at a temperature $T_1$ and the solvent at a temperature $T_2$,the elevation of boiling point is given by:

Exactly $1 \ g$ of urea dissolved in $75 \ g$ of water gives a solution that boils at $100.114 \ ^oC$ at $760 \ torr$. The molecular weight of urea is $60.1$. The boiling point elevation constant for water is

When a substance is dissolved in a solvent,the vapour pressure of the solvent is decreased. This results in:

What is the molal elevation constant if one gram mole of a nonvolatile solute is dissolved in $1 \ kg$ of ethyl acetate? $(\Delta T_{b} = x \ K)$