What is the bond order in CO molecule? | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) According to Molecular Orbital Theory,the bond order is calculated as $\frac{N_b - N_a}{2}$,where $N_b$ is the number of bonding electrons and $N_

Vedclass · Accepted Answer

$3$

Vedclass · Answer

(B) According to Molecular Orbital Theory,the bond order is calculated as $\frac{N_b - N_a}{2}$,where $N_b$ is the number of bonding electrons and $N_a$ is the number of antibonding electrons. For $CO$ molecule,the total number of electrons is $6 + 8 = 14$. The molecular orbital configuration is $\sigma 1s^2, \sigma^* 1s^2, \sigma 2s^2, \sigma^* 2s^2, \pi 2p_x^2 = \pi 2p_y^2, \sigma 2p_z^2$. Here,$N_b = 10$ and $N_a = 4$. Bond order = $\frac{10 - 4}{2} = \frac{6}{2} = 3$.

List-$I$	List-$II$
$(a)$ $Ne_2$	$(i)$ $1$
$(b)$ $N_2$	$(ii)$ $2$
$(c)$ $F_2$	$(iii)$ $0$
$(d)$ $O_2$	$(iv)$ $3$

What is the bond order in $CO$ molecule?

Similar Questions

The common features among the species $CN^{-}$,$CO$ and $NO^{+}$ are

Which among the following molecules exhibits paramagnetism?

Match List-$I$ with List-$II$ based on the bond order of the molecules.

List-$I$ List-$II$

$(a)$ $Ne_2$ $(i)$ $1$

$(b)$ $N_2$ $(ii)$ $2$

$(c)$ $F_2$ $(iii)$ $0$

$(d)$ $O_2$ $(iv)$ $3$

Choose the correct answer from the options given below:

The theory that can completely/properly explain the nature of bonding in $[Ni(CO)_4]$ is

Which of the following contains a $(2C - 1e^-)$ bond?

Vedclass Test Series

Exam Paper Generator

Online Exam Module