(B) The formula for conductivity $(\kappa)$ is given by: $\kappa = \frac{1}{R} \times \frac{\ell}{A}$ Where $\frac{\ell}{A}$ is the cell constant. Giv

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$2.0 \times 10^{-3} \ \Omega^{-1} \ cm^{-1}$

(B) The formula for conductivity $(\kappa)$ is given by: $\kappa = \frac{1}{R} \times \frac{\ell}{A}$ Where $\frac{\ell}{A}$ is the cell constant. Given: $R = 645 \ \Omega$ and $\text{Cell constant} = 1.29 \ cm^{-1}$. Substituting the values: $\kappa = \frac{1}{645} \times 1.29$ $\kappa = 0.002 \ \Omega^{-1} \ cm^{-1}$ $\kappa = 2 \times 10^{-3} \ \Omega^{-1} \ cm^{-1}$

Class 12 Chemistry Electrochemistry Conductor and Conductance and Cell constant

Difficult

What is the conductivity of $0.02 \ M \ KCl$ solution if the cell constant is $1.29 \ cm^{-1}$ and the resistance is $645 \ \Omega$?

MHT CET 2021 All MHT CET

A
$5.0 \times 10^{-3} \ \Omega^{-1} \ cm^{-1}$
B
$2.0 \times 10^{-3} \ \Omega^{-1} \ cm^{-1}$
C
$8.3 \times 10^{-3} \ \Omega^{-1} \ cm^{-1}$
D
$2.5 \times 10^{-3} \ \Omega^{-1} \ cm^{-1}$

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What is the conductivity of $0.02 \ M \ KCl$ solution if the cell constant is $1.29 \ cm^{-1}$ and the resistance is $645 \ \Omega$?

Similar Questions

What is the molar conductivity of $CH_3COOH$ at infinite dilution if the molar conductivities of $H_2SO_4$, $K_2SO_4$, and $CH_3COOK$ at infinite dilution are $x$, $y$, and $z$ $\Omega^{-1} \text{cm}^2 \text{mol}^{-1}$ respectively?

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