What is the conductivity of a semiconductor s | vedclass

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(A) The conductivity of a semiconductor is given by the formula:$\sigma = e(n_e \mu_e + n_h \mu_h)$Given values:$e = 1.6 	imes 10^{-19} \, C$$n_e = 5

Vedclass · Accepted Answer

$1.68$

Vedclass · Answer

(A) The conductivity of a semiconductor is given by the formula:$\sigma = e(n_e \mu_e + n_h \mu_h)$Given values:$e = 1.6 	imes 10^{-19} \, C$$n_e = 5 	imes 10^{18} \, m^{-3}$$n_h = 5 	imes 10^{19} \, m^{-3}$$\mu_e = 2.0 \, m^2 \, V^{-1} \, s^{-1}$$\mu_h = 0.01 \, m^2 \, V^{-1} \, s^{-1}$Substituting these values into the formula:$\sigma = 1.6 	imes 10^{-19} 	imes [(5 	imes 10^{18} 	imes 2.0) + (5 	imes 10^{19} 	imes 0.01)]$$\sigma = 1.6 	imes 10^{-19} 	imes [10 	imes 10^{18} + 0.05 	imes 10^{19}]$$\sigma = 1.6 	imes 10^{-19} 	imes [10^{19} + 0.5 	imes 10^{18}]$$\sigma = 1.6 	imes 10^{-19} 	imes [10 	imes 10^{18} + 0.5 	imes 10^{18}]$$\sigma = 1.6 	imes 10^{-19} 	imes [10.5 	imes 10^{18}]$$\sigma = 1.6 	imes 1.05 = 1.68 \, (\Omega \cdot m)^{-1}$

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