What is the correct IUPAC name of the coordin | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) $1$. The given coordination compound is $	ext{Hg[Co(SCN)}_4]$.$2$. The compound dissociates into $	ext{Hg}^{2+}$ and $	ext{[Co(SCN)}_4]^{2-}$.$

Vedclass · Accepted Answer

Mercury$(II)$ tetrathiocyanato-$S$-cobaltate$(II)$

Vedclass · Answer

(A) $1$. The given coordination compound is $	ext{Hg[Co(SCN)}_4]$.$2$. The compound dissociates into $	ext{Hg}^{2+}$ and $	ext{[Co(SCN)}_4]^{2-}$.$3$. In the complex anion $	ext{[Co(SCN)}_4]^{2-}$, the ligand is thiocyanate $(SCN^-)$, which is bonded through the sulfur atom, hence it is named 'thiocyanato-$S$'.$4$. Let the oxidation state of cobalt $(Co)$ be $x$. Since the charge on the complex is $-2$ and the charge on $SCN^-$ is $-1$, we have: $x + 4(-1) = -2$, which gives $x = +2$.$5$. The cation is mercury, which is in the $+2$ oxidation state, so it is named 'Mercury$(II)$'.$6$. The complex anion is named 'tetrathiocyanato-$S$-cobaltate$(II)$' because the metal is in an anionic complex.$7$. Combining these, the correct $IUPAC$ name is 'Mercury$(II)$ tetrathiocyanato-$S$-cobaltate$(II)$'.

What is the correct $IUPAC$ name of the coordination compound $\text{Hg[Co(SCN)}_4]$?

Similar Questions

The $IUPAC$ name of $[Pt(NH_3)_3(Br)(NO_2)Cl]$ is ......

The proper name for $K_2[PtCl_6]$ is

The oxidation number of cobalt in $K[Co(CO)_4]$ is
$(i)$ $+1$ $(ii)$ $+3$ $(iii)$ $-1$ $(iv)$ $-3$

The $IUPAC$ name of the coordination compound $K_3[Fe(CN)_6]$ is

$IUPAC$ name of $[Pt(NH_3)_3(Br)(NO_2)Cl]Cl$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module