What is the effect of the following processes on the bond order in $N_{2}$ and $O_{2}$?
$(A)$ $N_{2} \to N_{2}^{+} + e^{-}$
$(B)$ $O_{2} \to O_{2}^{+} + e^{-}$

(N/A) According to molecular orbital theory,the electronic configurations and bond order of $N_{2}$,$N_{2}^{+}$,$O_{2}$,and $O_{2}^{+}$ species are as follows:
$N_{2} (14 \ e^{-}) = \sigma 1s^{2}, \sigma^{*} 1s^{2}, \sigma 2s^{2}, \sigma^{*} 2s^{2}, (\pi 2p_{x}^{2} \approx \pi 2p_{y}^{2}), \sigma 2p_{z}^{2}$
Bond order $= \frac{1}{2} (N_{b} - N_{a}) = \frac{1}{2} (10 - 4) = 3$
$N_{2}^{+} (13 \ e^{-}) = \sigma 1s^{2}, \sigma^{*} 1s^{2}, \sigma 2s^{2}, \sigma^{*} 2s^{2}, (\pi 2p_{x}^{2} \approx \pi 2p_{y}^{2}), \sigma 2p_{z}^{1}$
Bond order $= \frac{1}{2} (9 - 4) = 2.5$
$O_{2} (16 \ e^{-}) = \sigma 1s^{2}, \sigma^{*} 1s^{2}, \sigma 2s^{2}, \sigma^{*} 2s^{2}, \sigma 2p_{z}^{2}, (\pi 2p_{x}^{2} \approx \pi 2p_{y}^{2}), (\pi^{*} 2p_{x}^{1} \approx \pi^{*} 2p_{y}^{1})$
Bond order $= \frac{1}{2} (10 - 6) = 2$
$O_{2}^{+} (15 \ e^{-}) = \sigma 1s^{2}, \sigma^{*} 1s^{2}, \sigma 2s^{2}, \sigma^{*} 2s^{2}, \sigma 2p_{z}^{2}, (\pi 2p_{x}^{2} \approx \pi 2p_{y}^{2}), \pi^{*} 2p_{x}^{1}$
Bond order $= \frac{1}{2} (10 - 5) = 2.5$
$(A)$ For $N_{2} \to N_{2}^{+} + e^{-}$,the bond order changes from $3$ to $2.5$. Thus,the bond order decreases.
$(B)$ For $O_{2} \to O_{2}^{+} + e^{-}$,the bond order changes from $2$ to $2.5$. Thus,the bond order increases.