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(D) The energy of an electron in the $n^{th}$ orbit of a hydrogen-like atom is given by the formula:$E_n = -R_H 	imes \frac{Z^2}{n^2} \ J$For a hydro

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$-0.136 	imes 10^{-18} \ J$

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(D) The energy of an electron in the $n^{th}$ orbit of a hydrogen-like atom is given by the formula:$E_n = -R_H 	imes \frac{Z^2}{n^2} \ J$For a hydrogen atom,the atomic number $Z = 1$.For the fourth orbit,$n = 4$.Substituting the values:$E_4 = -2.18 	imes 10^{-18} 	imes \frac{1^2}{4^2} \ J$$E_4 = -2.18 	imes 10^{-18} 	imes \frac{1}{16} \ J$$E_4 = -0.13625 	imes 10^{-18} \ J \approx -0.136 	imes 10^{-18} \ J$

What is the energy associated with the fourth orbit of a hydrogen atom?
$R_H = 2.18 \times 10^{-18} \ J$

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What is the energy associated with the fourth orbit of a hydrogen atom?$R_H = 2.18 \times 10^{-18} \ J$