(A) The given reaction is: $N_2 + O_2 \rightleftharpoons 2 NO$The equilibrium constant expression is given by:$K_C = \frac{[NO]^2}{[N_2][O_2]}$Given e

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

(A) The given reaction is: $N_2 + O_2 \rightleftharpoons 2 NO$The equilibrium constant expression is given by:$K_C = \frac{[NO]^2}{[N_2][O_2]}$Given equilibrium concentrations:$[N_2] = 4 \times 10^{-3} \ M$$[O_2] = 3 \times 10^{-3} \ M$$[NO] = 3 \times 10^{-3} \ M$Substituting the values into the expression:$K_C = \frac{(3 \times 10^{-3})^2}{(4 \times 10^{-3})(3 \times 10^{-3})}$$K_C = \frac{9 \times 10^{-6}}{12 \times 10^{-6}}$$K_C = \frac{9}{12} = 0.75$

Class 11 Chemistry 6-1.Equilibrium (Chemical Equilibrium)Law of equilibrium and Equilibrium constant

Medium

What is the equilibrium constant $(K_C)$ for the given reaction?
$N_2 + O_2 \rightleftharpoons 2 NO$
Where the equilibrium concentrations of $N_2$,$O_2$ and $NO$ are found to be $4 \times 10^{-3} \ M$,$3 \times 10^{-3} \ M$ and $3 \times 10^{-3} \ M$ respectively.

TS EAMCET 2020 All TS EAMCET

A
$0.75$
B
$0.622$
C
$9 \times 10^{-3}$
D
$12.8 \times 10^{-6}$

Explore More

Browse All

Question Bank

All Subjects

Class 11 Questions

Class 11

Chemistry Questions

Chapter

6-1.Equilibrium (Chemical Equilibrium)

Subtopic

Law of equilibrium and Equilibrium constant

Previous Year

TS EAMCET 2020 Paper All TS EAMCET years →

For the reaction $2 H_{2(g)} + 2 NO_{(g)} \rightarrow N_{2(g)} + 2 H_2O_{(g)}$,the observed rate expression is $rate = k_f [NO]^2 [H_2]$. The rate expression of the reverse reaction is:

MediumJEE MAIN 2020

View Solution

For the system $3A + 2B \rightleftharpoons C$,the expression for equilibrium constant is

Medium

View Solution

$A$ reaction with reaction quotient $Q_C$ and equilibrium constant $K_C$ will proceed in the direction of the products when:

MediumKVPY 2012

View Solution

If the equilibrium constant for $N_{2(g)} + O_{2(g)} \rightleftharpoons 2NO_{(g)}$ is $K,$ the equilibrium constant for $\frac{1}{2} N_{2(g)} + \frac{1}{2} O_{2(g)} \rightleftharpoons NO_{(g)}$ will be

MediumNEET 2015

View Solution

For the reaction $CaCO_{3(s)} \rightleftharpoons CaO_{(s)} + CO_{2(g)}$,which of the following expressions for the equilibrium constant $K_p$ is correct?

Medium

View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial

For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free

For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo

What is the equilibrium constant $(K_C)$ for the given reaction?$N_2 + O_2 \rightleftharpoons 2 NO$Where the equilibrium concentrations of $N_2$,$O_2$ and $NO$ are found to be $4 \times 10^{-3} \ M$,$3 \times 10^{-3} \ M$ and $3 \times 10^{-3} \ M$ respectively.

Similar Questions

For the reaction $2 H_{2(g)} + 2 NO_{(g)} \rightarrow N_{2(g)} + 2 H_2O_{(g)}$,the observed rate expression is $rate = k_f [NO]^2 [H_2]$. The rate expression of the reverse reaction is:

For the system $3A + 2B \rightleftharpoons C$,the expression for equilibrium constant is

$A$ reaction with reaction quotient $Q_C$ and equilibrium constant $K_C$ will proceed in the direction of the products when:

If the equilibrium constant for $N_{2(g)} + O_{2(g)} \rightleftharpoons 2NO_{(g)}$ is $K,$ the equilibrium constant for $\frac{1}{2} N_{2(g)} + \frac{1}{2} O_{2(g)} \rightleftharpoons NO_{(g)}$ will be

For the reaction $CaCO_{3(s)} \rightleftharpoons CaO_{(s)} + CO_{2(g)}$,which of the following expressions for the equilibrium constant $K_p$ is correct?

Vedclass Test Series

Exam Paper Generator

Online Exam Module

What is the equilibrium constant $(K_C)$ for the given reaction?
$N_2 + O_2 \rightleftharpoons 2 NO$
Where the equilibrium concentrations of $N_2$,$O_2$ and $NO$ are found to be $4 \times 10^{-3} \ M$,$3 \times 10^{-3} \ M$ and $3 \times 10^{-3} \ M$ respectively.