What is the equivalent weight of $KMnO_4$ in acidic medium (in $g$)? (Molecular weight of $KMnO_4 = 158 \ g$)

  • A
    $158$
  • B
    $52.7$
  • C
    $31.6$
  • D
    $39.5$

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Similar Questions

Consider the following reaction occurring in basic medium $2MnO_4^- (aq) + Br^- (aq) \to 2MnO_2 (s) + BrO_3^- (aq)$. How can the above reaction be balanced further?

Which of the following is a redox reaction?

$MnO_4^- + C_2O_4^{2-} + H^+ \to Mn^{2+} + CO_2 + H_2O$ :
What are the correct stoichiometric coefficients for the balanced redox reaction?

Difficult
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Calculate the value of $n$ in the given reaction:
$MnO_4^{-} + 8H^{+} + n e^{-} \to Mn^{+2} + 4H_2O$

Assign $A$,$B$,$C$,$D$ from the given type of reaction.
$Ca_{(s)} + 2H_2O_{(l)} \xrightarrow{R.T.} Ca(OH)_{2(aq)} + H_{2(g)} \uparrow$

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