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(D) The reaction of benzonitrile $(C_6H_5CN)$ with phenyl magnesium bromide $(C_6H_5MgBr)$ in dry ether proceeds via a nucleophilic addition to the ni

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Benzophenone

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(D) The reaction of benzonitrile $(C_6H_5CN)$ with phenyl magnesium bromide $(C_6H_5MgBr)$ in dry ether proceeds via a nucleophilic addition to the nitrile group.$1$. The phenyl group from the Grignard reagent attacks the electrophilic carbon of the nitrile group to form an imine magnesium bromide complex $(C_6H_5-C(C_6H_5)=NMgBr)$.$2$. Upon subsequent acid hydrolysis $(H_3O^+)$,the imine complex is converted into a ketone.$3$. The final product formed is benzophenone $(C_6H_5-CO-C_6H_5)$.

What is the final product obtained when benzonitrile reacts with phenyl magnesium bromide in equimolar proportion?

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